What are the solutions to the equation 4x^2-20x+25=0 ?

The solutions to the equation 4x^2-20x+25=0 are x= 5/2

Find the zeros of 4x^2-20x+25=0

The zeros of 4x^2-20x+25=0 are x= 5/2

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4 x^{2} - 20 x + 25 = 0

x = \frac{5}{2}

Solution steps

4 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

The solution to the quadratic equation is:

x = \frac{5}{2}

100 a^{2} + 600 a + 500

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 2}

q^{2} a^{2} + 2 q^{2} + 27 a - 9 a^{2} - 3 q^{2} a - 18

3 x^{7} - 27 x

5 y^{- 3}

What are the solutions to the equation 4x^2-20x+25=0 ?
The solutions to the equation 4x^2-20x+25=0 are x= 5/2
Find the zeros of 4x^2-20x+25=0
The zeros of 4x^2-20x+25=0 are x= 5/2