What is 1/x+1/(x+1)< 2/(x+2) ?

The solution to 1/x+1/(x+1)< 2/(x+2) is -2<x<-1\lor-2/3 <x<0

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1/x+1/(x+1)< 2/(x+2)

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 2}

- 2 < x < - 1 or - \frac{2}{3} < x < 0

Interval Notation

(- 2, - 1) \cup (- \frac{2}{3}, 0)

Decimal Notation

- 2 < x < - 1 or - 0.66666 \dots < x < 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 2}

Rewrite in standard form

\frac{3 x + 2}{x ( x + 1 ) ( x + 2 )} < 0

Identify the intervals

- 2 < x < - 1 or - \frac{2}{3} < x < 0

q^{2} a^{2} + 2 q^{2} + 27 a - 9 a^{2} - 3 q^{2} a - 18

3 x^{7} - 27 x

5 y^{- 3}

x^{2} + 8 x + 16 = 3

x - 20 > 24

What is 1/x+1/(x+1)< 2/(x+2) ?
The solution to 1/x+1/(x+1)< 2/(x+2) is -2<x<-1\lor-2/3 <x<0