What are the solutions to the equation 54-9x+54+9x=4x^2+144 ?

The solutions to the equation 54-9x+54+9x=4x^2+144 are x=3i,x=-3i

Find the zeros of 54-9x+54+9x=4x^2+144

The zeros of 54-9x+54+9x=4x^2+144 are x=3i,x=-3i

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54 - 9 x + 54 + 9 x = 4 x^{2} + 144

x = 3 i, x = - 3 i

Solution steps

54 - 9 x + 54 + 9 x = 4 x^{2} + 144

Switch sides

4 x^{2} + 144 = 54 - 9 x + 54 + 9 x

Move

144

to the right side

4 x^{2} = - 36

Divide both sides by

4

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

s^{2} + 58 s + 399 = 0

\frac{12 !}{( 12 - 5 ) ! 5 !}

\frac{11}{6} = \frac{p + 4}{12}

x^{2} + 21 x < 46

- 216 = - 8 x - 88

What are the solutions to the equation 54-9x+54+9x=4x^2+144 ?
The solutions to the equation 54-9x+54+9x=4x^2+144 are x=3i,x=-3i
Find the zeros of 54-9x+54+9x=4x^2+144
The zeros of 54-9x+54+9x=4x^2+144 are x=3i,x=-3i