What are the solutions to the equation s^2+58s+399=0 ?

The solutions to the equation s^2+58s+399=0 are s=-29+sqrt(442),s=-29-sqrt(442)

Find the zeros of s^2+58s+399=0

The zeros of s^2+58s+399=0 are s=-29+sqrt(442),s=-29-sqrt(442)

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s^{2} + 58 s + 399 = 0

s = - 29 + 442, s = - 29 - 442

Decimal Notation

s = - 7.97620 \dots, s = - 50.02379 \dots

Solution steps

s^{2} + 58 s + 399 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 58 \pm 5 8 ^{2} - 4 \cdot 1 \cdot 399}{2 \cdot 1}

5 8^{2} - 4 \cdot 1 \cdot 399 = 2442

s_{1, 2} = \frac{- 58 \pm 2 442}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 58 + 2 442}{2 \cdot 1}, s_{2} = \frac{- 58 - 2 442}{2 \cdot 1}

s = \frac{- 58 + 2 442}{2 \cdot 1} : - 29 + 442

s = \frac{- 58 - 2 442}{2 \cdot 1} : - 29 - 442

The solutions to the quadratic equation are:

s = - 29 + 442, s = - 29 - 442

\frac{12 !}{( 12 - 5 ) ! 5 !}

\frac{11}{6} = \frac{p + 4}{12}

x^{2} + 21 x < 46

- 216 = - 8 x - 88

72 = 2 π r^{2}

What are the solutions to the equation s^2+58s+399=0 ?
The solutions to the equation s^2+58s+399=0 are s=-29+sqrt(442),s=-29-sqrt(442)
Find the zeros of s^2+58s+399=0
The zeros of s^2+58s+399=0 are s=-29+sqrt(442),s=-29-sqrt(442)