What are the solutions to the equation 10x^2+23x-42=0 ?

The solutions to the equation 10x^2+23x-42=0 are x= 6/5 ,x=-7/2

Find the zeros of 10x^2+23x-42=0

The zeros of 10x^2+23x-42=0 are x= 6/5 ,x=-7/2

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10 x^{2} + 23 x - 42 = 0

x = \frac{6}{5}, x = - \frac{7}{2}

Decimal Notation

x = 1.2, x = - 3.5

Solution steps

10 x^{2} + 23 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 10 ( - 42 )}{2 \cdot 10}

2 3^{2} - 4 \cdot 10 (- 42) = 47

x_{1, 2} = \frac{- 23 \pm 47}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 23 + 47}{2 \cdot 10}, x_{2} = \frac{- 23 - 47}{2 \cdot 10}

x = \frac{- 23 + 47}{2 \cdot 10} : \frac{6}{5}

x = \frac{- 23 - 47}{2 \cdot 10} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - \frac{7}{2}

(\frac{2}{3} \cdot \frac{4}{5}) + \frac{2}{5} - \frac{3}{10}

25 m^{2} - 81 n^{2}

5 x^{2} + 7 x - 2 = 0

17.95 + 0.82 x = 172.11

k (k + 40) - 10 k + 20 k = 490

What are the solutions to the equation 10x^2+23x-42=0 ?
The solutions to the equation 10x^2+23x-42=0 are x= 6/5 ,x=-7/2
Find the zeros of 10x^2+23x-42=0
The zeros of 10x^2+23x-42=0 are x= 6/5 ,x=-7/2