What is (-sqrt(7)(1+i))/(sqrt(3)+i) ?

The solution to (-sqrt(7)(1+i))/(sqrt(3)+i) is -(sqrt(7)((sqrt(3)+1)+(-1+sqrt(3))i))/4

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simplify (-sqrt(7)(1+i))/(sqrt(3)+i)

simplify

\frac{- 7 ( 1 + i )}{3 + i}

- \frac{7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4}

Solution steps

\frac{- 7 ( 1 + i )}{3 + i}

Multiply by the conjugate

\frac{3 - i}{3 - i}

= \frac{- 7 ( 1 + i ) ( 3 - i )}{( 3 + i ) ( 3 - i )}

Simplify

\frac{- 7 ( 1 + i ) ( 3 - i )}{( 3 + i ) ( 3 - i )} : \frac{- 7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4}

= \frac{- 7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4}

Simplify

\frac{- 7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4} : - \frac{7 ( 3 + 1 + ( - 1 + 3 ) i )}{4}

= - \frac{7 ( 3 + 1 + ( - 1 + 3 ) i )}{4}

Rewrite in standard complex form:

- \frac{7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4}

= - \frac{7 ( ( 3 + 1 ) + ( - 1 + 3 ) i )}{4}

\frac{4 !}{3 !}

2^{2} - 5

0 = x^{2} + 4 x

4 \cdot \frac{3}{4}

b^{2} - 4 = 0

What is (-sqrt(7)(1+i))/(sqrt(3)+i) ?
The solution to (-sqrt(7)(1+i))/(sqrt(3)+i) is -(sqrt(7)((sqrt(3)+1)+(-1+sqrt(3))i))/4