What are the solutions to the equation 0=-16t^2+160t+0 ?

The solutions to the equation 0=-16t^2+160t+0 are t=0,t=10

Find the zeros of 0=-16t^2+160t+0

The zeros of 0=-16t^2+160t+0 are t=0,t=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 t^{2} + 160 t + 0

t = 0, t = 10

Solution steps

0 = - 16 t^{2} + 160 t + 0

Refine

0 = - 16 t^{2} + 160 t

Switch sides

- 16 t^{2} + 160 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

16 0^{2} - 4 (- 16) \cdot 0 = 160

t_{1, 2} = \frac{- 160 \pm 160}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 160 + 160}{2 ( - 16 )}, t_{2} = \frac{- 160 - 160}{2 ( - 16 )}

t = \frac{- 160 + 160}{2 ( - 16 )} : 0

t = \frac{- 160 - 160}{2 ( - 16 )} : 10

The solutions to the quadratic equation are:

t = 0, t = 10

4 x^{2} - 9 x + 5 = 0

(2 + i) (2 - i)

(\frac{5}{2})^{4}

∣ x - 4 ∣ > 3

3 m^{3} + 3 m^{2} - 18 m

What are the solutions to the equation 0=-16t^2+160t+0 ?
The solutions to the equation 0=-16t^2+160t+0 are t=0,t=10
Find the zeros of 0=-16t^2+160t+0
The zeros of 0=-16t^2+160t+0 are t=0,t=10