What are the solutions to the equation (2x+7)^2=64 ?

The solutions to the equation (2x+7)^2=64 are x= 1/2 ,x=-15/2

Find the zeros of (2x+7)^2=64

The zeros of (2x+7)^2=64 are x= 1/2 ,x=-15/2

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(2 x + 7)^{2} = 64

x = \frac{1}{2}, x = - \frac{15}{2}

Decimal Notation

x = 0.5, x = - 7.5

Solution steps

(2 x + 7)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 7 = 64 : x = \frac{1}{2}

Solve

2 x + 7 = - 64 : x = - \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{15}{2}

4 0^{2} + 9^{2} = x^{2}

\frac{10 !}{2 ! ( 10 - 2 ) !}

(- 125 x^{- 6})^{\frac{1}{3}}

\frac{3}{4} x + 8 < 41

x^{2} + 24 x + 144 = 9

What are the solutions to the equation (2x+7)^2=64 ?
The solutions to the equation (2x+7)^2=64 are x= 1/2 ,x=-15/2
Find the zeros of (2x+7)^2=64
The zeros of (2x+7)^2=64 are x= 1/2 ,x=-15/2