What are the solutions to the equation r^2-8r+13=0 ?

The solutions to the equation r^2-8r+13=0 are r=4+sqrt(3),r=4-sqrt(3)

Find the zeros of r^2-8r+13=0

The zeros of r^2-8r+13=0 are r=4+sqrt(3),r=4-sqrt(3)

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r^{2} - 8 r + 13 = 0

r = 4 + 3, r = 4 - 3

Decimal Notation

r = 5.73205 \dots, r = 2.26794 \dots

Solution steps

r^{2} - 8 r + 13 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 13 = 23

r_{1, 2} = \frac{- ( - 8 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 3}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 3}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 3}{2 \cdot 1} : 4 + 3

r = \frac{- ( - 8 ) - 2 3}{2 \cdot 1} : 4 - 3

The solutions to the quadratic equation are:

r = 4 + 3, r = 4 - 3

- 4 x + 5 + 3 x = 2 - x + 3

∣ x - 8 ∣ = - 1

\frac{x - 12}{4} + \frac{x}{2} + \frac{x - 2 x}{9} = 0

x^{3} - 6 x^{2} - 15 x - 8

4 x^{2} = 8 x

What are the solutions to the equation r^2-8r+13=0 ?
The solutions to the equation r^2-8r+13=0 are r=4+sqrt(3),r=4-sqrt(3)
Find the zeros of r^2-8r+13=0
The zeros of r^2-8r+13=0 are r=4+sqrt(3),r=4-sqrt(3)