What are the solutions to the equation 0=3x^2+4x+1 ?

The solutions to the equation 0=3x^2+4x+1 are x=-1/3 ,x=-1

Find the zeros of 0=3x^2+4x+1

The zeros of 0=3x^2+4x+1 are x=-1/3 ,x=-1

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0 = 3 x^{2} + 4 x + 1

x = - \frac{1}{3}, x = - 1

Decimal Notation

x = - 0.33333 \dots, x = - 1

Solution steps

0 = 3 x^{2} + 4 x + 1

Switch sides

3 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

4^{2} - 4 \cdot 3 \cdot 1 = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 \cdot 3}, x_{2} = \frac{- 4 - 2}{2 \cdot 3}

x = \frac{- 4 + 2}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 4 - 2}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 1

4 x^{2} - 4 x + 21 = 0

\frac{11}{6} - \frac{9}{2}

3 x^{2} + 20 x - 32

\frac{25}{100} \cdot 50

3 (x + 2) < 5 (x + 3)

What are the solutions to the equation 0=3x^2+4x+1 ?
The solutions to the equation 0=3x^2+4x+1 are x=-1/3 ,x=-1
Find the zeros of 0=3x^2+4x+1
The zeros of 0=3x^2+4x+1 are x=-1/3 ,x=-1