What is factor (2x^2-10x)/(x^2-4x-5) ?

The solution to factor (2x^2-10x)/(x^2-4x-5) is (2x)/(x+1)

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factor (2x^2-10x)/(x^2-4x-5)

factor

\frac{2 x ^{2} - 10 x}{x ^{2} - 4 x - 5}

\frac{2 x}{x + 1}

Solution steps

\frac{2 x ^{2} - 10 x}{x ^{2} - 4 x - 5}

Factor out common term

2 x : 2 x (x - 5)

= \frac{2 x ( x - 5 )}{x ^{2} - 4 x - 5}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{2 x ( x - 5 )}{( x + 1 ) ( x - 5 )}

Cancel the common factor:

x - 5

= \frac{2 x}{x + 1}

\frac{36}{64}

\frac{- 21}{- 7}

- \frac{x}{4} < 12

5 x (2 x + 1) - 3 (2 x + 1) = 0

\frac{5}{6} - \frac{3}{5} + \frac{1}{2}

What is factor (2x^2-10x)/(x^2-4x-5) ?
The solution to factor (2x^2-10x)/(x^2-4x-5) is (2x)/(x+1)