What are the solutions to the equation 5x(2x+1)-3(2x+1)=0 ?

The solutions to the equation 5x(2x+1)-3(2x+1)=0 are x= 3/5 ,x=-1/2

Find the zeros of 5x(2x+1)-3(2x+1)=0

The zeros of 5x(2x+1)-3(2x+1)=0 are x= 3/5 ,x=-1/2

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5 x (2 x + 1) - 3 (2 x + 1) = 0

x = \frac{3}{5}, x = - \frac{1}{2}

Decimal Notation

x = 0.6, x = - 0.5

Solution steps

5 x (2 x + 1) - 3 (2 x + 1) = 0

Expand

5 x (2 x + 1) - 3 (2 x + 1) : 10 x^{2} - x - 3

10 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 3 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 3) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 10}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 10}

x = \frac{- ( - 1 ) + 11}{2 \cdot 10} : \frac{3}{5}

x = \frac{- ( - 1 ) - 11}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{1}{2}

\frac{5}{6} - \frac{3}{5} + \frac{1}{2}

3 x + 8 = 12 - x

p^{2} - 4 p = 0

(x + 7)^{2} = \frac{49}{16}

\frac{4 + 6 i}{3 i}

What are the solutions to the equation 5x(2x+1)-3(2x+1)=0 ?
The solutions to the equation 5x(2x+1)-3(2x+1)=0 are x= 3/5 ,x=-1/2
Find the zeros of 5x(2x+1)-3(2x+1)=0
The zeros of 5x(2x+1)-3(2x+1)=0 are x= 3/5 ,x=-1/2