What are the solutions to the equation p^2-4p=0 ?

The solutions to the equation p^2-4p=0 are p=4,p=0

Find the zeros of p^2-4p=0

The zeros of p^2-4p=0 are p=4,p=0

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p^{2} - 4 p = 0

p = 4, p = 0

Solution steps

p^{2} - 4 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

p_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, p_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

p = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

p = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 4, p = 0

(x + 7)^{2} = \frac{49}{16}

\frac{4 + 6 i}{3 i}

x < 3 (x^{2} - 2 x + 1)

5 - 53 i

x^{2} + 4 x - 41 = 0

What are the solutions to the equation p^2-4p=0 ?
The solutions to the equation p^2-4p=0 are p=4,p=0
Find the zeros of p^2-4p=0
The zeros of p^2-4p=0 are p=4,p=0