What are the solutions to the equation x^2+(12/13)^2=1 ?

The solutions to the equation x^2+(12/13)^2=1 are x= 5/13 ,x=-5/13

Find the zeros of x^2+(12/13)^2=1

The zeros of x^2+(12/13)^2=1 are x= 5/13 ,x=-5/13

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x^{2} + (\frac{12}{13})^{2} = 1

x = \frac{5}{13}, x = - \frac{5}{13}

Decimal Notation

x = 0.38461 \dots, x = - 0.38461 \dots

Solution steps

x^{2} + (\frac{12}{13})^{2} = 1

Expand

x^{2} + (\frac{12}{13})^{2} : x^{2} + \frac{144}{169}

x^{2} + \frac{144}{169} = 1

Move

\frac{144}{169}

to the right side

x^{2} = 1 - \frac{144}{169}

Simplify

1 - \frac{144}{169} : \frac{25}{169}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{169}, x = - \frac{25}{169}

\frac{25}{169} = \frac{5}{13}

- \frac{25}{169} = - \frac{5}{13}

x = \frac{5}{13}, x = - \frac{5}{13}

3 x^{2} - 6

0 < 2 x - 2 \leq 6

8 + 96 t - 16 t^{2} = 116

4 m^{2} = 6

∣ x ∣ \geq 8

What are the solutions to the equation x^2+(12/13)^2=1 ?
The solutions to the equation x^2+(12/13)^2=1 are x= 5/13 ,x=-5/13
Find the zeros of x^2+(12/13)^2=1
The zeros of x^2+(12/13)^2=1 are x= 5/13 ,x=-5/13