What are the solutions to the equation 8x^2+6x+1=0 ?

The solutions to the equation 8x^2+6x+1=0 are x=-1/4 ,x=-1/2

Find the zeros of 8x^2+6x+1=0

The zeros of 8x^2+6x+1=0 are x=-1/4 ,x=-1/2

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8 x^{2} + 6 x + 1 = 0

x = - \frac{1}{4}, x = - \frac{1}{2}

Decimal Notation

x = - 0.25, x = - 0.5

Solution steps

8 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

6^{2} - 4 \cdot 8 \cdot 1 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 8}, x_{2} = \frac{- 6 - 2}{2 \cdot 8}

x = \frac{- 6 + 2}{2 \cdot 8} : - \frac{1}{4}

x = \frac{- 6 - 2}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{1}{2}

12 x^{2} + 69 x + 45

7 (x - 1) = 2 (3 x + 1)

5 - \frac{1}{5}

7 x^{x} (\frac{6 y}{21 x})

- 3 < - 2 x + 1 \leq 9

What are the solutions to the equation 8x^2+6x+1=0 ?
The solutions to the equation 8x^2+6x+1=0 are x=-1/4 ,x=-1/2
Find the zeros of 8x^2+6x+1=0
The zeros of 8x^2+6x+1=0 are x=-1/4 ,x=-1/2