What is 7x^x((6y)/(21x)) ?

The solution to 7x^x((6y)/(21x)) is 2x^{x-1}y

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simplify 7x^x((6y)/(21x))

simplify

7 x^{x} (\frac{6 y}{21 x})

2 x^{x - 1} y

Solution steps

7 x^{x} (\frac{6 y}{21 x})

Apply rule:

(a) = a

(\frac{6 y}{21 x}) = \frac{6 y}{21 x}

= 7 x^{x} \frac{6 y}{21 x}

Cancel

\frac{6 y}{21 x} : \frac{2 y}{7 x}

= 7 x^{x} \frac{2 y}{7 x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 x ^{x} \cdot 2 y}{7 x}

Cancel the common factor:

7

= \frac{x ^{x} \cdot 2 y}{x}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{x}}{x ^{1}} = x^{x - 1}

= x^{x - 1} \cdot 2 y

= 2 x^{x - 1} y

- 3 < - 2 x + 1 \leq 9

\frac{5}{2} = \frac{1}{3} (x - 2)

\frac{6 - 2 x}{3} - \frac{2}{3} = - 1

4 x^{2} + 9 = 17

(a^{3})^{2}