What is (32x^3y)/(y^8)*(y^7)/(8x^4) ?

The solution to (32x^3y)/(y^8)*(y^7)/(8x^4) is 4/x

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simplify (32x^3y)/(y^8)*(y^7)/(8x^4)

simplify

\frac{32 x ^{3} y}{y ^{8}} \cdot \frac{y ^{7}}{8 x ^{4}}

\frac{4}{x}

Solution steps

\frac{32 x ^{3} y}{y ^{8}} \cdot \frac{y ^{7}}{8 x ^{4}}

Cancel

\frac{32 x ^{3} y}{y ^{8}} : \frac{32 x ^{3}}{y ^{7}}

= \frac{32 x ^{3}}{y ^{7}} \cdot \frac{y ^{7}}{8 x ^{4}}

Cross-cancel common factor:

y^{7}

= \frac{32 x ^{3}}{8 x ^{4}}

Simplify

\frac{x ^{3}}{x ^{4}} : \frac{1}{x}

= \frac{32}{8 x}

Factor the number:

32 = 8 \cdot 4

= \frac{8 \cdot 4}{8 x}

Cancel the common factor:

8

= \frac{4}{x}

10 x^{2} - 17 x - 6

- 5 + (- 2)

2^{2} + 4^{2} = c^{2}

- 1 > z + 5

10000 \cdot \frac{1}{( 1 + 0.05 ) ^{3}}

What is (32x^3y)/(y^8)*(y^7)/(8x^4) ?
The solution to (32x^3y)/(y^8)*(y^7)/(8x^4) is 4/x