What are the solutions to the equation 49x^2-25=0 ?

The solutions to the equation 49x^2-25=0 are x= 5/7 ,x=-5/7

Find the zeros of 49x^2-25=0

The zeros of 49x^2-25=0 are x= 5/7 ,x=-5/7

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49 x^{2} - 25 = 0

x = \frac{5}{7}, x = - \frac{5}{7}

Decimal Notation

x = 0.71428 \dots, x = - 0.71428 \dots

Solution steps

49 x^{2} - 25 = 0

Move

25

to the right side

49 x^{2} = 25

Divide both sides by

49

x^{2} = \frac{25}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{49}, x = - \frac{25}{49}

\frac{25}{49} = \frac{5}{7}

- \frac{25}{49} = - \frac{5}{7}

x = \frac{5}{7}, x = - \frac{5}{7}

3 x^{2} - 8 = 12

1 0^{2} + 9^{2} = x^{2}

\frac{13}{4} + \frac{19}{5}

5 x - 15 y

(- 5)^{- 4}

What are the solutions to the equation 49x^2-25=0 ?
The solutions to the equation 49x^2-25=0 are x= 5/7 ,x=-5/7
Find the zeros of 49x^2-25=0
The zeros of 49x^2-25=0 are x= 5/7 ,x=-5/7