What are the solutions to the equation 2x^2-6x=-4 ?

The solutions to the equation 2x^2-6x=-4 are x=2,x=1

Find the zeros of 2x^2-6x=-4

The zeros of 2x^2-6x=-4 are x=2,x=1

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2 x^{2} - 6 x = - 4

x = 2, x = 1

Solution steps

2 x^{2} - 6 x = - 4

Move

4

to the left side

2 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 \cdot 4 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2}{2 \cdot 2} : 2

x = \frac{- ( - 6 ) - 2}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

5 + m > - 2

4 j^{2} + 8 j + 3

\frac{6 x ^{2}}{( \frac{4 x}{y} \cdot \frac{3 y ^{2}}{2} )}

\frac{4}{3} x + 3 = 19

lo g_{8} (16) = x

What are the solutions to the equation 2x^2-6x=-4 ?
The solutions to the equation 2x^2-6x=-4 are x=2,x=1
Find the zeros of 2x^2-6x=-4
The zeros of 2x^2-6x=-4 are x=2,x=1