What is 14x-3>=-1\land-3(x-2)>= 2 ?

The solution to 14x-3>=-1\land-3(x-2)>= 2 is 1/7 <= x<= 4/3

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14x-3>=-1\land-3(x-2)>= 2

14 x - 3 \geq - 1 and - 3 (x - 2) \geq 2

\frac{1}{7} \leq x \leq \frac{4}{3}

Solution steps

14 x - 3 \geq - 1 and - 3 (x - 2) \geq 2

14 x - 3 \geq - 1 : x \geq \frac{1}{7}

- 3 (x - 2) \geq 2 : x \leq \frac{4}{3}

Combine the intervals

x \geq \frac{1}{7} and x \leq \frac{4}{3}

Merge Overlapping Intervals

\frac{1}{7} \leq x \leq \frac{4}{3}

\frac{4 ( 9 ) ^{\frac{1}{2}}}{9}

\frac{3 π}{4} - 2 π

x^{2} + 2 x = 3

x + 4 \geq 5 and 8 x \geq 24

\frac{90 - a}{2} - a

What is 14x-3>=-1\land-3(x-2)>= 2 ?
The solution to 14x-3>=-1\land-3(x-2)>= 2 is 1/7 <= x<= 4/3