What are the solutions to the equation x^2+2x=3 ?

The solutions to the equation x^2+2x=3 are x=1,x=-3

Find the zeros of x^2+2x=3

The zeros of x^2+2x=3 are x=1,x=-3

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x^{2} + 2 x = 3

x = 1, x = - 3

Solution steps

x^{2} + 2 x = 3

Move

3

to the left side

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

x + 4 \geq 5 and 8 x \geq 24

\frac{1}{2 ^{7}}

\frac{90 - a}{2} - a

z^{2} - z - 30 = 0

- 4 x + 2 < 2 x - 6

What are the solutions to the equation x^2+2x=3 ?
The solutions to the equation x^2+2x=3 are x=1,x=-3
Find the zeros of x^2+2x=3
The zeros of x^2+2x=3 are x=1,x=-3