What are the solutions to the equation -x^2+1x-5/4 =0 ?

The solutions to the equation -x^2+1x-5/4 =0 are x= 1/2-i,x= 1/2+i

Find the zeros of -x^2+1x-5/4 =0

The zeros of -x^2+1x-5/4 =0 are x= 1/2-i,x= 1/2+i

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- x^{2} + 1 x - \frac{5}{4} = 0

x = \frac{1}{2} - i, x = \frac{1}{2} + i

Solution steps

- x^{2} + 1 \cdot x - \frac{5}{4} = 0

Multiply both sides by

4

- 4 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) ( - 5 )}{2 ( - 4 )}

Simplify

4^{2} - 4 (- 4) (- 5) : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 ( - 4 )}, x_{2} = \frac{- 4 - 8 i}{2 ( - 4 )}

x = \frac{- 4 + 8 i}{2 ( - 4 )} : \frac{1}{2} - i

x = \frac{- 4 - 8 i}{2 ( - 4 )} : \frac{1}{2} + i

The solutions to the quadratic equation are:

x = \frac{1}{2} - i, x = \frac{1}{2} + i

\frac{2}{3} x - \frac{1}{3} \geq 3

28 + 463 - 27

2 x^{3} - x^{2} - 50 x + 25

x^{2} - 11 x + 28

y^{2} + 16 y = 17

What are the solutions to the equation -x^2+1x-5/4 =0 ?
The solutions to the equation -x^2+1x-5/4 =0 are x= 1/2-i,x= 1/2+i
Find the zeros of -x^2+1x-5/4 =0
The zeros of -x^2+1x-5/4 =0 are x= 1/2-i,x= 1/2+i