What are the solutions to the equation y^2+16y=17 ?

The solutions to the equation y^2+16y=17 are y=1,y=-17

Find the zeros of y^2+16y=17

The zeros of y^2+16y=17 are y=1,y=-17

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y^{2} + 16 y = 17

y = 1, y = - 17

Solution steps

y^{2} + 16 y = 17

Move

17

to the left side

y^{2} + 16 y - 17 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 17) = 18

y_{1, 2} = \frac{- 16 \pm 18}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 18}{2 \cdot 1}, y_{2} = \frac{- 16 - 18}{2 \cdot 1}

y = \frac{- 16 + 18}{2 \cdot 1} : 1

y = \frac{- 16 - 18}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

y = 1, y = - 17

lo g_{e} (0)

k^{2} = 0.49

x^{2} + \frac{5}{2} x + 1 = 0

- p - 4 p = 0

\frac{4}{b - 8} + \frac{7}{b ^{2} - 64}

What are the solutions to the equation y^2+16y=17 ?
The solutions to the equation y^2+16y=17 are y=1,y=-17
Find the zeros of y^2+16y=17
The zeros of y^2+16y=17 are y=1,y=-17