What are the solutions to the equation x^2+5/2 x+1=0 ?

The solutions to the equation x^2+5/2 x+1=0 are x=-1/2 ,x=-2

Find the zeros of x^2+5/2 x+1=0

The zeros of x^2+5/2 x+1=0 are x=-1/2 ,x=-2

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x^{2} + \frac{5}{2} x + 1 = 0

x = - \frac{1}{2}, x = - 2

Solution steps

x^{2} + \frac{5}{2} x + 1 = 0

Multiply both sides by

2

2 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 2}, x_{2} = \frac{- 5 - 3}{2 \cdot 2}

x = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

- p - 4 p = 0

\frac{4}{b - 8} + \frac{7}{b ^{2} - 64}

x^{10}

n^{4} - 100

∣ 2 x + 6 ∣ + 18 \geq 6

What are the solutions to the equation x^2+5/2 x+1=0 ?
The solutions to the equation x^2+5/2 x+1=0 are x=-1/2 ,x=-2
Find the zeros of x^2+5/2 x+1=0
The zeros of x^2+5/2 x+1=0 are x=-1/2 ,x=-2