What is 4/(b-8)+7/(b^2-64) ?

The solution to 4/(b-8)+7/(b^2-64) is (4b+39)/((b-8)(b+8))

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simplify 4/(b-8)+7/(b^2-64)

simplify

\frac{4}{b - 8} + \frac{7}{b ^{2} - 64}

\frac{4 b + 39}{( b - 8 ) ( b + 8 )}

Solution steps

\frac{4}{b - 8} + \frac{7}{b ^{2} - 64}

Least Common Multiplier of

b - 8, b^{2} - 64 : (b - 8) (b + 8)

Adjust Fractions based on the LCM

= \frac{4 ( b + 8 )}{( b - 8 ) ( b + 8 )} + \frac{7}{( b - 8 ) ( b + 8 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{4 ( b + 8 ) + 7}{( b - 8 ) ( b + 8 )}

Simplify

4 (b + 8) + 7 : 4 b + 39

= \frac{4 b + 39}{( b - 8 ) ( b + 8 )}

x^{10}

n^{4} - 100

∣ 2 x + 6 ∣ + 18 \geq 6

3 k^{2} - 30 k + 87 = 0

66 - x^{2} + x = 10

What is 4/(b-8)+7/(b^2-64) ?
The solution to 4/(b-8)+7/(b^2-64) is (4b+39)/((b-8)(b+8))