What are the solutions to the equation 6x^2-15x-7=-10x-6 ?

The solutions to the equation 6x^2-15x-7=-10x-6 are x=1,x=-1/6

Find the zeros of 6x^2-15x-7=-10x-6

The zeros of 6x^2-15x-7=-10x-6 are x=1,x=-1/6

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6 x^{2} - 15 x - 7 = - 10 x - 6

x = 1, x = - \frac{1}{6}

Solution steps

6 x^{2} - 15 x - 7 = - 10 x - 6

Move

6

to the left side

6 x^{2} - 15 x - 1 = - 10 x

Move

10 x

to the left side

6 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 1) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 6}

x = \frac{- ( - 5 ) + 7}{2 \cdot 6} : 1

x = \frac{- ( - 5 ) - 7}{2 \cdot 6} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{6}

5 x + 48 + 7 x = 12 (x + 4)

- 4 p + 9 = - 5

(x + 3) \cdot (x - 4) + x \cdot (x + 2) = 2 - x^{2}

∣ x - 5 ∣ < 2

x^{2} - 17 x + 16 = 0

What are the solutions to the equation 6x^2-15x-7=-10x-6 ?
The solutions to the equation 6x^2-15x-7=-10x-6 are x=1,x=-1/6
Find the zeros of 6x^2-15x-7=-10x-6
The zeros of 6x^2-15x-7=-10x-6 are x=1,x=-1/6