What is the answer to 3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x) ?

The answer to 3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x) is x= 13/3

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3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x)

3 \cdot (2 x - 6) - [(x - (3 x - 8) + 2) - 1] = 2 - (3 - 2 x)

x = \frac{13}{3}

Solution steps

3 (2 x - 6) - [(x - (3 x - 8) + 2) - 1] = 2 - (3 - 2 x)

3 (2 x - 6) - (x - (3 x - 8) + 2 - 1) = 2 - (3 - 2 x)

Expand

3 (2 x - 6) - (x - (3 x - 8) + 2 - 1) : 8 x - 27

Expand

2 - (3 - 2 x) : 2 x - 1

8 x - 27 = 2 x - 1

Move

27

to the right side

8 x = 2 x + 26

Move

2 x

to the left side

6 x = 26

Divide both sides by

6

x = \frac{13}{3}

(4.56 + d) - (4.56 - d) = 0.26425195

- x^{2} + x - 1 = 0

∣ 2 x + 7 ∣ < 3

(a^{5})^{2}

0.157 = 0.0003 x - 1^{- 5}

What is the answer to 3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x) ?
The answer to 3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x) is x= 13/3
Solve for x: 3*(2x-6)-[(x-(3x-8)+2)-1]=2-(3-2x)
The solution is x= 13/3