What is |3-x^2|<=-2x+4 ?

The solution to |3-x^2|<=-2x+4 is -2sqrt(2)-1<= x<= 2sqrt(2)-1

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|3-x^2|<=-2x+4

3 - x^{2} \leq - 2 x + 4

- 22 - 1 \leq x \leq 22 - 1

Interval Notation

[- 22 - 1, 22 - 1]

Decimal Notation

- 3.82842 \dots \leq x \leq 1.82842 \dots

Solution steps

3 - x^{2} \leq - 2 x + 4

Find positive and negative intervals

x < - 3, - 3 \leq x \leq 3, x > 3

Solve the inequality for each interval

- 22 - 1 \leq x < - 3 or - 3 \leq x \leq 3 or 3 < x \leq 22 - 1

Merge Overlapping Intervals

- 22 - 1 \leq x \leq 22 - 1

x^{2} - \frac{5}{6} x + \frac{1}{6} = 0

1058

m^{2} + 2 m = 8

- 1 \cdot - 1

ln (e)

What is |3-x^2|<=-2x+4 ?
The solution to |3-x^2|<=-2x+4 is -2sqrt(2)-1<= x<= 2sqrt(2)-1