What are the solutions to the equation 0=x^2+4x+4 ?

The solutions to the equation 0=x^2+4x+4 are x=-2

Find the zeros of 0=x^2+4x+4

The zeros of 0=x^2+4x+4 are x=-2

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0 = x^{2} + 4 x + 4

x = - 2

Solution steps

0 = x^{2} + 4 x + 4

Switch sides

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} + 8 x = 33

(1 + 3 i)^{3}

- 3 24 a^{4} b^{2} c^{3}

\frac{1}{25} - 16 z^{2}

3 - 2 (x - 3) = 4

What are the solutions to the equation 0=x^2+4x+4 ?
The solutions to the equation 0=x^2+4x+4 are x=-2
Find the zeros of 0=x^2+4x+4
The zeros of 0=x^2+4x+4 are x=-2