What are the solutions to the equation 2x^2+6x-10=x^2+6 ?

The solutions to the equation 2x^2+6x-10=x^2+6 are x=2,x=-8

Find the zeros of 2x^2+6x-10=x^2+6

The zeros of 2x^2+6x-10=x^2+6 are x=2,x=-8

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2 x^{2} + 6 x - 10 = x^{2} + 6

x = 2, x = - 8

Solution steps

2 x^{2} + 6 x - 10 = x^{2} + 6

Move

6

to the left side

2 x^{2} + 6 x - 16 = x^{2}

Move

x^{2}

to the left side

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

2 x^{2} + 3 = 0

(- 1)^{\frac{2}{5}}

9 - 4 x^{2}

x^{3} y - 25 x y

(x^{- \frac{2}{3}} y^{- \frac{1}{2}})^{2}

What are the solutions to the equation 2x^2+6x-10=x^2+6 ?
The solutions to the equation 2x^2+6x-10=x^2+6 are x=2,x=-8
Find the zeros of 2x^2+6x-10=x^2+6
The zeros of 2x^2+6x-10=x^2+6 are x=2,x=-8