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Popular >

sqrt(0.5x^2+1)<= 5x

Solution

0.5 x^{2} + 1 \leq 5 x

Solution

x \geq \frac{2}{7}

+2

Solution steps

0.5 x^{2} + 1 \leq 5 x

If

f (x) \leq g (x)

then

g (x) \geq 0

5 x \geq 0 : x \geq 0

0.5 x^{2} + 1 \leq 5 x : x \leq - \frac{2}{7} or x \geq \frac{2}{7}

Verify Solutions:

x \geq \frac{2}{7}

True

The solution is

x \geq \frac{2}{7}

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(x - 5)^{2} + 4 (x - 5) - 5 = 0

simplify (5pi)/6+(2pi)/3 simplify

\frac{5 π}{6} + \frac{2 π}{3}

5 x - 6 = 8

9 x^{2} - 7 = 18

Frequently Asked Questions (FAQ)

What is sqrt(0.5x^2+1)<= 5x ?
The solution to sqrt(0.5x^2+1)<= 5x is x>= (sqrt(2))/7