What is (9x(x^3-2))/((x^3+1)^3)<= 0 ?

The solution to (9x(x^3-2))/((x^3+1)^3)<= 0 is x<-1\lor 0<= x<= \sqrt[3]{2}

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(9x(x^3-2))/((x^3+1)^3)<= 0

\frac{9 x ( x ^{3} - 2 )}{( x ^{3} + 1 ) ^{3}} \leq 0

Interval Notation

Decimal Notation

x < - 1 or 0 \leq x \leq 1.25992 \dots

Solution steps

\frac{9 x ( x ^{3} - 2 )}{( x ^{3} + 1 ) ^{3}} \leq 0

Rewrite in standard form

\frac{x ( x ^{3} - 2 )}{( x ^{3} + 1 ) ^{3}} \leq 0

Factor

Identify the intervals

920

\frac{48}{52} \cdot \frac{47}{51} \cdot \frac{46}{50}

4 n^{2} + n - 33

- 2 x - 10 < 8 + 8 x

x^{2} - 4 x + 8

What is (9x(x^3-2))/((x^3+1)^3)<= 0 ?
The solution to (9x(x^3-2))/((x^3+1)^3)<= 0 is x<-1\lor 0<= x<= \sqrt[3]{2}