What is the answer to (2+3i)^2-(3i-6)=1+9i ?

The answer to (2+3i)^2-(3i-6)=1+9i is True

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(2+3i)^2-(3i-6)=1+9i

(2 + 3 i)^{2} - (3 i - 6) = 1 + 9 i

True

Solution steps

(2 + 3 i)^{2} - (3 i - 6) = 1 + 9 i

Simplify

(2 + 3 i)^{2} - (3 i - 6) : 1 + 9 i

1 + 9 i = 1 + 9 i

Both sides are equal

True

x^{3} + 7 x^{2} - 2 x - 14

6 x^{2} - 7 x - 49 = 0

5 x^{2} - 12 x + 8 = 5

3 - \frac{4 x}{5} = 2

\frac{1}{- 4 + 2 i}

What is the answer to (2+3i)^2-(3i-6)=1+9i ?
The answer to (2+3i)^2-(3i-6)=1+9i is True
Solve for i: (2+3i)^2-(3i-6)=1+9i
The solution is True