What are the solutions to the equation 64y^2=25 ?

The solutions to the equation 64y^2=25 are y= 5/8 ,y=-5/8

Find the zeros of 64y^2=25

The zeros of 64y^2=25 are y= 5/8 ,y=-5/8

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64 y^{2} = 25

y = \frac{5}{8}, y = - \frac{5}{8}

Solution steps

64 y^{2} = 25

Divide both sides by

64

y^{2} = \frac{25}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{25}{64}, y = - \frac{25}{64}

\frac{25}{64} = \frac{5}{8}

- \frac{25}{64} = - \frac{5}{8}

y = \frac{5}{8}, y = - \frac{5}{8}

- 4 x^{2} + 12 x - 9 = 0

\frac{1}{2} (- 6 w + 8) - 5 = 3 w - 1

\frac{1}{2} x^{2} = \frac{2}{5} x^{2}

(5 - 7 i) (8 + 13 i)

- \frac{3}{5} x \geq 18

What are the solutions to the equation 64y^2=25 ?
The solutions to the equation 64y^2=25 are y= 5/8 ,y=-5/8
Find the zeros of 64y^2=25
The zeros of 64y^2=25 are y= 5/8 ,y=-5/8