What are the solutions to the equation (y+2)^2+140=0 ?

The solutions to the equation (y+2)^2+140=0 are y=2sqrt(35)i-2,y=-2sqrt(35)i-2

Find the zeros of (y+2)^2+140=0

The zeros of (y+2)^2+140=0 are y=2sqrt(35)i-2,y=-2sqrt(35)i-2

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(y + 2)^{2} + 140 = 0

y = 235 i - 2, y = - 235 i - 2

Solution steps

(y + 2)^{2} + 140 = 0

Move

140

to the right side

(y + 2)^{2} = - 140

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 2 = - 140 : y = 235 i - 2

Solve

y + 2 = - - 140 : y = - 235 i - 2

The solutions to the quadratic equation are:

y = 235 i - 2, y = - 235 i - 2

3 n - 5 > 17 + 8 n

3^{2} + x^{2} = 1 3^{2}

r^{2} + 3 r - 3 = 0

x^{4} + 2 x^{2} y^{2} + y^{4}

3 x + 1 = 0

What are the solutions to the equation (y+2)^2+140=0 ?
The solutions to the equation (y+2)^2+140=0 are y=2sqrt(35)i-2,y=-2sqrt(35)i-2
Find the zeros of (y+2)^2+140=0
The zeros of (y+2)^2+140=0 are y=2sqrt(35)i-2,y=-2sqrt(35)i-2