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Popular >

x^2+2x+1<x^2+8

Solution

x^{2} + 2 x + 1 < x^{2} + 8

Solution

x < \frac{7}{2}

+2

Interval Notation

(- \infty, \frac{7}{2})

Decimal Notation

x < 3.5

Solution steps

x^{2} + 2 x + 1 < x^{2} + 8

Rewrite in standard form

2 x - 7 < 0

Move

7

to the right side

2 x < 7

Divide both sides by

2

x < \frac{7}{2}

Popular Examples

15 = 8 x^{2} - 14 x

-2<= (2x-6)/6 <= 4

- 2 \leq \frac{2 x - 6}{6} \leq 4

x^2+(x+2)^2=(x-14)^2

x^{2} + (x + 2)^{2} = (x - 14)^{2}

- 2 x + 6 + 4 x = - 12

9 c + 4 \leq 22

Frequently Asked Questions (FAQ)

What is x^2+2x+1<x^2+8 ?
The solution to x^2+2x+1<x^2+8 is x< 7/2