What are the solutions to the equation x^2-5x+20=0 ?

The solutions to the equation x^2-5x+20=0 are x= 5/2+i(sqrt(55))/2 ,x= 5/2-i(sqrt(55))/2

Find the zeros of x^2-5x+20=0

The zeros of x^2-5x+20=0 are x= 5/2+i(sqrt(55))/2 ,x= 5/2-i(sqrt(55))/2

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x^{2} - 5 x + 20 = 0

x = \frac{5}{2} + i \frac{55}{2}, x = \frac{5}{2} - i \frac{55}{2}

Solution steps

x^{2} - 5 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 20 : 55 i

x_{1, 2} = \frac{- ( - 5 ) \pm 55 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 55 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 55 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 55 i}{2 \cdot 1} : \frac{5}{2} + i \frac{55}{2}

x = \frac{- ( - 5 ) - 55 i}{2 \cdot 1} : \frac{5}{2} - i \frac{55}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{55}{2}, x = \frac{5}{2} - i \frac{55}{2}

- 4 x^{2} + 56 x + 0 = 0

\frac{- 1 - 2 i}{- 1 + 2 i}

(1 + \frac{0.06}{4})^{4}

\frac{1}{2 + 3}

200 x - x^{2} = 5 x + 6200

What are the solutions to the equation x^2-5x+20=0 ?
The solutions to the equation x^2-5x+20=0 are x= 5/2+i(sqrt(55))/2 ,x= 5/2-i(sqrt(55))/2
Find the zeros of x^2-5x+20=0
The zeros of x^2-5x+20=0 are x= 5/2+i(sqrt(55))/2 ,x= 5/2-i(sqrt(55))/2