What are the solutions to the equation 3x^2+8x-7=0 ?

The solutions to the equation 3x^2+8x-7=0 are x=(-4+sqrt(37))/3 ,x=-(4+sqrt(37))/3

Find the zeros of 3x^2+8x-7=0

The zeros of 3x^2+8x-7=0 are x=(-4+sqrt(37))/3 ,x=-(4+sqrt(37))/3

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3 x^{2} + 8 x - 7 = 0

x = \frac{- 4 + 37}{3}, x = - \frac{4 + 37}{3}

Decimal Notation

x = 0.69425 \dots, x = - 3.36092 \dots

Solution steps

3 x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 7) = 237

x_{1, 2} = \frac{- 8 \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 2 37}{2 \cdot 3}, x_{2} = \frac{- 8 - 2 37}{2 \cdot 3}

x = \frac{- 8 + 2 37}{2 \cdot 3} : \frac{- 4 + 37}{3}

x = \frac{- 8 - 2 37}{2 \cdot 3} : - \frac{4 + 37}{3}

The solutions to the quadratic equation are:

x = \frac{- 4 + 37}{3}, x = - \frac{4 + 37}{3}

8 (3 x + 2) - 5 (2 x - 1) = 8 - (9 - 3 x)

\frac{4}{18}

162

5 x^{4} - 6 x^{2} + 1

2 x^{2} - 10 x - 3 = 0

What are the solutions to the equation 3x^2+8x-7=0 ?
The solutions to the equation 3x^2+8x-7=0 are x=(-4+sqrt(37))/3 ,x=-(4+sqrt(37))/3
Find the zeros of 3x^2+8x-7=0
The zeros of 3x^2+8x-7=0 are x=(-4+sqrt(37))/3 ,x=-(4+sqrt(37))/3