What are the solutions to the equation 9^2+40^2=x^2 ?

The solutions to the equation 9^2+40^2=x^2 are x=41,x=-41

Find the zeros of 9^2+40^2=x^2

The zeros of 9^2+40^2=x^2 are x=41,x=-41

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9^{2} + 4 0^{2} = x^{2}

x = 41, x = - 41

Solution steps

9^{2} + 4 0^{2} = x^{2}

Switch sides

x^{2} = 9^{2} + 4 0^{2}

Simplify

9^{2} + 4 0^{2} : 1681

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1681, x = - 1681

1681 = 41

- 1681 = - 41

x = 41, x = - 41

49 w^{2} - 64

72 y^{2} = 13 y + 15

6 \cdot \frac{π}{180}

6 + 2 y + 3 x^{2} + x^{2} y

\frac{- 16 w ^{7} r ^{2}}{- 4 w r}

What are the solutions to the equation 9^2+40^2=x^2 ?
The solutions to the equation 9^2+40^2=x^2 are x=41,x=-41
Find the zeros of 9^2+40^2=x^2
The zeros of 9^2+40^2=x^2 are x=41,x=-41