What are the solutions to the equation 9((25y^2)/4+40y+64)=0 ?

The solutions to the equation 9((25y^2)/4+40y+64)=0 are y=-16/5

Find the zeros of 9((25y^2)/4+40y+64)=0

The zeros of 9((25y^2)/4+40y+64)=0 are y=-16/5

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9 (\frac{25 y ^{2}}{4} + 40 y + 64) = 0

y = - \frac{16}{5}

Decimal Notation

y = - 3.2

Solution steps

9 (\frac{25 y ^{2}}{4} + 40 y + 64) = 0

Expand

9 (\frac{25 y ^{2}}{4} + 40 y + 64) : \frac{225 y ^{2}}{4} + 360 y + 576

\frac{225 y ^{2}}{4} + 360 y + 576 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 360 \pm 36 0 ^{2} - 4 \cdot \frac{225}{4} \cdot 576}{2 \cdot \frac{225}{4}}

36 0^{2} - 4 \cdot \frac{225}{4} \cdot 576 = 0

y_{1, 2} = \frac{- 360 \pm 0}{2 \cdot \frac{225}{4}}

y = \frac{- 360}{2 \cdot \frac{225}{4}}

\frac{- 360}{2 \cdot \frac{225}{4}} = - \frac{16}{5}

y = - \frac{16}{5}

The solution to the quadratic equation is:

y = - \frac{16}{5}

2 x^{2} + 9 = 4 x

x^{3} + 3 x^{2} - 10 x

\frac{3}{8} + \frac{a}{2}

- 3 \geq x

x^{2} = 9 - 4 x

What are the solutions to the equation 9((25y^2)/4+40y+64)=0 ?
The solutions to the equation 9((25y^2)/4+40y+64)=0 are y=-16/5
Find the zeros of 9((25y^2)/4+40y+64)=0
The zeros of 9((25y^2)/4+40y+64)=0 are y=-16/5