What are the solutions to the equation 15x^2+20=40x ?

The solutions to the equation 15x^2+20=40x are x=2,x= 2/3

Find the zeros of 15x^2+20=40x

The zeros of 15x^2+20=40x are x=2,x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

15 x^{2} + 20 = 40 x

x = 2, x = \frac{2}{3}

Decimal Notation

x = 2, x = 0.66666 \dots

Solution steps

15 x^{2} + 20 = 40 x

Move

40 x

to the left side

15 x^{2} + 20 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} - 40 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 15 \cdot 20}{2 \cdot 15}

(- 40)^{2} - 4 \cdot 15 \cdot 20 = 20

x_{1, 2} = \frac{- ( - 40 ) \pm 20}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 20}{2 \cdot 15}, x_{2} = \frac{- ( - 40 ) - 20}{2 \cdot 15}

x = \frac{- ( - 40 ) + 20}{2 \cdot 15} : 2

x = \frac{- ( - 40 ) - 20}{2 \cdot 15} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{3}

8 c^{2} + 10 c - 7

2^{2} + 11 x + 5 = 0

x^{3} \cdot x^{2}

7 q^{2} - 28 = 0

8 a^{4} - 2 a + 12 a^{3}

What are the solutions to the equation 15x^2+20=40x ?
The solutions to the equation 15x^2+20=40x are x=2,x= 2/3
Find the zeros of 15x^2+20=40x
The zeros of 15x^2+20=40x are x=2,x= 2/3