What is (2z)/3-(3z)/4+(4z)/5-(5z)/6 <7 ?

The solution to (2z)/3-(3z)/4+(4z)/5-(5z)/6 -60

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(2z)/3-(3z)/4+(4z)/5-(5z)/6 <7

\frac{2 z}{3} - \frac{3 z}{4} + \frac{4 z}{5} - \frac{5 z}{6} < 7

z > - 60

Interval Notation

(- 60, \infty)

Solution steps

\frac{2 z}{3} - \frac{3 z}{4} + \frac{4 z}{5} - \frac{5 z}{6} < 7

Multiply by LCM

- 7 z < 420

Multiply both sides by

- 1

7 z > - 420

Divide both sides by

7

z > - 60

0 = x - 3 \cdot 16.1

- x^{2} + 9

- 1 y - 14 = 0

8 x^{2} - 9 = - 8 x

- \frac{9}{n ^{3}} (\frac{( n ( n + 1 ) ( 2 n + 1 ) )}{6}) - 24

What is (2z)/3-(3z)/4+(4z)/5-(5z)/6 <7 ?
The solution to (2z)/3-(3z)/4+(4z)/5-(5z)/6 <7 is z>-60