What are the solutions to the equation 36r^2+84r+49=0 ?

The solutions to the equation 36r^2+84r+49=0 are r=-7/6

Find the zeros of 36r^2+84r+49=0

The zeros of 36r^2+84r+49=0 are r=-7/6

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36 r^{2} + 84 r + 49 = 0

r = - \frac{7}{6}

Decimal Notation

r = - 1.16666 \dots

Solution steps

36 r^{2} + 84 r + 49 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 84 \pm 8 4 ^{2} - 4 \cdot 36 \cdot 49}{2 \cdot 36}

8 4^{2} - 4 \cdot 36 \cdot 49 = 0

r_{1, 2} = \frac{- 84 \pm 0}{2 \cdot 36}

r = \frac{- 84}{2 \cdot 36}

\frac{- 84}{2 \cdot 36} = - \frac{7}{6}

r = - \frac{7}{6}

The solution to the quadratic equation is:

r = - \frac{7}{6}

- 5 x - 3 < 17

\frac{6}{6 ^{\frac{1}{4}}}

2 n^{2} = - 144

2 c^{5} + 44 c^{4} + 242 c^{3}

What are the solutions to the equation 36r^2+84r+49=0 ?
The solutions to the equation 36r^2+84r+49=0 are r=-7/6
Find the zeros of 36r^2+84r+49=0
The zeros of 36r^2+84r+49=0 are r=-7/6