What are the solutions to the equation (x+9)^2-7(x+9)-18=0 ?

The solutions to the equation (x+9)^2-7(x+9)-18=0 are x=0,x=-11

Find the zeros of (x+9)^2-7(x+9)-18=0

The zeros of (x+9)^2-7(x+9)-18=0 are x=0,x=-11

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(x + 9)^{2} - 7 (x + 9) - 18 = 0

x = 0, x = - 11

Solution steps

(x + 9)^{2} - 7 (x + 9) - 18 = 0

Expand

(x + 9)^{2} - 7 (x + 9) - 18 : x^{2} + 11 x

x^{2} + 11 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 0 = 11

x_{1, 2} = \frac{- 11 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 11}{2 \cdot 1}, x_{2} = \frac{- 11 - 11}{2 \cdot 1}

x = \frac{- 11 + 11}{2 \cdot 1} : 0

x = \frac{- 11 - 11}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 0, x = - 11

(- 4)^{6}

∣ 2 x + 5 ∣ < 3

2 x^{2} - x - 120 = 0

3 x - 12 \leq \frac{5 x - 6}{4}

- 14 x^{2} + 4 x + 14 = - 6 x^{2}

What are the solutions to the equation (x+9)^2-7(x+9)-18=0 ?
The solutions to the equation (x+9)^2-7(x+9)-18=0 are x=0,x=-11
Find the zeros of (x+9)^2-7(x+9)-18=0
The zeros of (x+9)^2-7(x+9)-18=0 are x=0,x=-11