What are the solutions to the equation x^2-3=4x ?

The solutions to the equation x^2-3=4x are x=2+sqrt(7),x=2-sqrt(7)

Find the zeros of x^2-3=4x

The zeros of x^2-3=4x are x=2+sqrt(7),x=2-sqrt(7)

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x^{2} - 3 = 4 x

x = 2 + 7, x = 2 - 7

Decimal Notation

x = 4.64575 \dots, x = - 0.64575 \dots

Solution steps

x^{2} - 3 = 4 x

Move

4 x

to the left side

x^{2} - 3 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

x = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

x = 2 + 7, x = 2 - 7

2 y^{2} + y + 10 = 0

lo g_{36} (\frac{1}{6})

\frac{48 x ^{3}}{3 x y ^{2}}

3 = y + 6

3 x^{2} + 10 x + 7

What are the solutions to the equation x^2-3=4x ?
The solutions to the equation x^2-3=4x are x=2+sqrt(7),x=2-sqrt(7)
Find the zeros of x^2-3=4x
The zeros of x^2-3=4x are x=2+sqrt(7),x=2-sqrt(7)