What are the solutions to the equation m^2-5m-14=0 ?

The solutions to the equation m^2-5m-14=0 are m=7,m=-2

Find the zeros of m^2-5m-14=0

The zeros of m^2-5m-14=0 are m=7,m=-2

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m^{2} - 5 m - 14 = 0

m = 7, m = - 2

Solution steps

m^{2} - 5 m - 14 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

m_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, m_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

m = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

m = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

m = 7, m = - 2

\frac{1}{27} x^{3} + \frac{1}{125} y^{3}

3 x^{3} - 24 x^{2} + 45 x

2 x + 6 = x + 14

b^{2} + 9 b - 14 = 6 b

x^{2} - x + 3 = 2 x^{2} - 5 x - 29

What are the solutions to the equation m^2-5m-14=0 ?
The solutions to the equation m^2-5m-14=0 are m=7,m=-2
Find the zeros of m^2-5m-14=0
The zeros of m^2-5m-14=0 are m=7,m=-2