What are the solutions to the equation (6x-7)^2+4=21 ?

The solutions to the equation (6x-7)^2+4=21 are x=(sqrt(17)+7)/6 ,x=(-sqrt(17)+7)/6

Find the zeros of (6x-7)^2+4=21

The zeros of (6x-7)^2+4=21 are x=(sqrt(17)+7)/6 ,x=(-sqrt(17)+7)/6

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(6 x - 7)^{2} + 4 = 21

x = \frac{17 + 7}{6}, x = \frac{- 17 + 7}{6}

Decimal Notation

x = 1.85385 \dots, x = 0.47948 \dots

Solution steps

(6 x - 7)^{2} + 4 = 21

Move

4

to the right side

(6 x - 7)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 x - 7 = 17 : x = \frac{17 + 7}{6}

Solve

6 x - 7 = - 17 : x = \frac{- 17 + 7}{6}

The solutions to the quadratic equation are:

x = \frac{17 + 7}{6}, x = \frac{- 17 + 7}{6}

0 = - \frac{41 t}{1000}

x^{2} + 4 x + 4 - 9 y^{2}

x^{2} - 2 x - 4 = 0

\frac{u ^{2} v ^{2}}{3 u ^{2} v ^{2}}

5 (x + 6)^{2} = 60

What are the solutions to the equation (6x-7)^2+4=21 ?
The solutions to the equation (6x-7)^2+4=21 are x=(sqrt(17)+7)/6 ,x=(-sqrt(17)+7)/6
Find the zeros of (6x-7)^2+4=21
The zeros of (6x-7)^2+4=21 are x=(sqrt(17)+7)/6 ,x=(-sqrt(17)+7)/6