What are the solutions to the equation x^2-sqrt(2)x-4=0 ?

The solutions to the equation x^2-sqrt(2)x-4=0 are x=2sqrt(2),x=-sqrt(2)

Find the zeros of x^2-sqrt(2)x-4=0

The zeros of x^2-sqrt(2)x-4=0 are x=2sqrt(2),x=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x - 4 = 0

x = 22, x = - 2

Decimal Notation

x = 2.82842 \dots, x = - 1.41421 \dots

Solution steps

x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 4) = 32

x_{1, 2} = \frac{- ( - 2 ) \pm 3 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 3 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 3 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 3 2}{2 \cdot 1} : 22

x = \frac{- ( - 2 ) - 3 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 22, x = - 2

\frac{u ^{2} v ^{2}}{3 u ^{2} v ^{2}}

5 (x + 6)^{2} = 60

12 - 3 x^{2}

x^{2} + 6 x y + 8 y^{2}

(3 x + 1)^{2} = 5

What are the solutions to the equation x^2-sqrt(2)x-4=0 ?
The solutions to the equation x^2-sqrt(2)x-4=0 are x=2sqrt(2),x=-sqrt(2)
Find the zeros of x^2-sqrt(2)x-4=0
The zeros of x^2-sqrt(2)x-4=0 are x=2sqrt(2),x=-sqrt(2)