What is ((x^6y^3)^{-1/3})/((x^4y^2)^{-1/2)} ?

The solution to ((x^6y^3)^{-1/3})/((x^4y^2)^{-1/2)} is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^6y^3)^{-1/3})/((x^4y^2)^{-1/2)}

simplify

\frac{( x ^{6} y ^{3} ) ^{- \frac{1}{3}}}{( x ^{4} y ^{2} ) ^{- \frac{1}{2}}}

1

Solution steps

\frac{( x ^{6} y ^{3} ) ^{- \frac{1}{3}}}{( x ^{4} y ^{2} ) ^{- \frac{1}{2}}}

Simplify

(x^{6} y^{3})^{- \frac{1}{3}} : \frac{1}{x ^{2}} \cdot \frac{1}{y}

= \frac{\frac{1}{x ^{2}} \cdot \frac{1}{y}}{( x ^{4} y ^{2} ) ^{- \frac{1}{2}}}

Simplify

(x^{4} y^{2})^{- \frac{1}{2}} : \frac{1}{x ^{2}} \cdot \frac{1}{y}

= \frac{\frac{1}{x ^{2}} \cdot \frac{1}{y}}{\frac{1}{x ^{2}} \cdot \frac{1}{y}}

Cancel the common factor:

\frac{1}{x ^{2}}

= \frac{\frac{1}{y}}{\frac{1}{y}}

Apply the fraction rule:

\frac{a}{a} = 1

= 1

5 x + 19 = 4 (x - 7)

(3 x + 4)^{2} - (x - 5)^{2}

7 x^{3} + 14 x^{2} + 7 x

- (8 x^{3} + 1) + (2 x + 1)^{3}

x^{2} - 4 x = - \frac{2}{11}

What is ((x^6y^3)^{-1/3})/((x^4y^2)^{-1/2)} ?
The solution to ((x^6y^3)^{-1/3})/((x^4y^2)^{-1/2)} is 1