What is factor-(8x^3+1)+(2x+1)^3 ?

The solution to factor-(8x^3+1)+(2x+1)^3 is 6x(2x+1)

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factor-(8x^3+1)+(2x+1)^3

factor

- (8 x^{3} + 1) + (2 x + 1)^{3}

6 x (2 x + 1)

Solution steps

- (8 x^{3} + 1) + (2 x + 1)^{3}

Factor

8 x^{3} + 1 : (2 x + 1) (4 x^{2} - 2 x + 1)

= - (2 x + 1) (4 x^{2} - 2 x + 1) + (2 x + 1)^{3}

Factor out common term

(2 x + 1) : (2 x + 1) (- (4 x^{2} - 2 x + 1) + (2 x + 1)^{2})

= (2 x + 1) (- (4 x^{2} - 2 x + 1) + (2 x + 1)^{2})

Expand

- (4 x^{2} - 2 x + 1) + (2 x + 1)^{2} : 6 x

= (2 x + 1) \cdot 6 x

= 6 x (2 x + 1)

x^{2} - 4 x = - \frac{2}{11}

2^{\frac{1}{2}} + 2^{\frac{1}{2}}

\frac{1}{15} - \frac{11}{12}

x^{2} - 3 x + 16 = 2 x^{2} - 3 x

x^{2} - 10 x + 25 = 1

What is factor-(8x^3+1)+(2x+1)^3 ?
The solution to factor-(8x^3+1)+(2x+1)^3 is 6x(2x+1)